Completing the Square Calculator
Complete the square for quadratics. Free online Completing the Square Calculator for algebra — instant, accurate results, mobile-friendly, no signup needed.
For ax² + bx + c = 0, show completing the square form.
Derivation
- ├── 01Given
a = 1, b = -6, c = 5 - ├── 02Formula
Vertex (h, k): {let t=e.a,a=e.b,n=e.c;return"(".concat((-a / (2 × t)).toFixed(4),", ").concat((n-a² / (4 × t)).toFixed(4),")")} - ├── 03Substitute
{let t=e.1,1=e.-6,n=e.5;return"(".concat((-1 / (2 × t)).toFixed(4),", ").concat((n-1² / (4 × t)).toFixed(4),")")} - ├── 04Compute Vertex (h, k)—
- ├── 05Formula
Form a(x−h)² + k: {let t=e.a,a=e.b,n=e.c;return"".concat(t,"(x \u2212 ").concat((-a / (2 × t)).toFixed(4),")\xb2 + ").concat((n-a² / (4 × t)).toFixed(4))} - ├── 06Substitute
{let t=e.1,1=e.-6,n=e.5;return"".concat(t,"(x \u2212 ").concat((-1 / (2 × t)).toFixed(4),")\xb2 + ").concat((n-1² / (4 × t)).toFixed(4))} - └── 07Compute Form a(x−h)² + k—
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Understanding the Completing the Square Calculator
The Completing the Square Calculator computes Vertex (h, k) from 3 inputs: a, b, c. Complete the square for quadratics.
Algebra is the art of solving for the unknown. Rearranging a formula to isolate the variable you actually need is the single most common real-world math skill — and doing it with real numbers under time pressure is where errors happen. The Completing the Square Calculator sits in that toolkit — it complete the square for quadratics. Enter your numbers above and the result updates instantly; every step of the math is shown in the Derivation panel so you can see exactly how the answer was reached.
How it’s calculated
Where
- a
- a
- b
- b
- c
- c
- Vertex (h, k)
- Output value
- Form a(x−h)² + k
- Output value
Step-by-step walkthrough
Apply the formula to a realistic set of inputs: a = 1, b = -6, c = 5.
- 01Start by noting the input — a: 1.
- 02Start by noting the input — b: -6.
- 03Start by noting the input — c: 5.
- 04Substitute these values into the formula: Vertex (h, k) = {let t=e.a,a=e.b,n=e.c;return"(".concat((-a / (2 × t)).toFixed(4),", ").concat((n-a² / (4 × t)).toFixed(4),")")} | For…
- 05Compute Vertex (h, k): the calculator returns (3.0000, -4.0000).
- 06Compute Form a(x−h)² + k: the calculator returns 1(x − 3.0000)² + -4.0000.
- 07Cross-check the answer by opening the Derivation panel above — every line of math is shown so you can follow the computation end-to-end.
Frequently asked questions
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